document.write( "Question 1198920: I'm saving money over a year in order to buy a $157.50 gift. I start with an empty piggy bank. In January I put in a small amount of money. Each month after January, I put in $1.75 more than I put in the previous month. By the end of December, I've saved $157.50 exactly. The amount in dollars that I had in my piggy bank after April's deposit was \n" ); document.write( "
Algebra.Com's Answer #832592 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "x = amount deposited in January\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the deposits increase by the same amount ($1.75) each month, we have an arithmetic sequence\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "a1 = first term = x \n" ); document.write( "d = common difference = 1.75 \n" ); document.write( "n = number of terms\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "We'll have n = 12 to represent the 12 months. \n" ); document.write( "Let's find the sum of the first 12 terms of this sequence. \n" ); document.write( "This will get the total amount saved after December's deposit.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sn = sum of the first n terms of an arithmetic sequence \n" ); document.write( "Sn = (n/2)*(2*a1+d*(n-1)) \n" ); document.write( "S12 = (12/2)*(2*x+1.75*(12-1)) \n" ); document.write( "S12 = 12x+115.5\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The sum of the first 12 terms of the sequence {x, x+1.75, (x+1.75)+1.75, etc} is 12x+115.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Set this equal to 157.50 which is the total amount saved at the end of December.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Solve for x. \n" ); document.write( "12x+115.5 = 157.50 \n" ); document.write( "12x = 157.50-115.5 \n" ); document.write( "12x = 42 \n" ); document.write( "x = 42/12 \n" ); document.write( "x = 3.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You deposited $3.50 into the piggybank in January to start things off. \n" ); document.write( "Then for February, the deposit is 3.50+1.75 = 5.25 and so on until you arrive at December.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I don't recommend writing out all the terms as the tutor @greenestamps has done, if doing it by hand. \n" ); document.write( "Though you can use computer software to do it for you. A spreadsheet is really handy in situations like this.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Let's return back to the summation formula mentioned earlier. \n" ); document.write( "This time we plug in n = 4 to determine how much is saved after April's deposit. \n" ); document.write( "I.e. this is the sum of the first four terms.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Sn = (n/2)*(2*a1+d*(n-1)) \n" ); document.write( "S4 = (4/2)*(2*3.5+1.75*(4-1)) \n" ); document.write( "S4 = 24.5\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Answer: $24.50 \n" ); document.write( " \n" ); document.write( " |