document.write( "Question 1198891: Let alpha be the arc such that: alpha belongs to ] pie over 2, pie[ and cos alpha= -12 over 13. Without using a calculator find sin alpha and tan alpha \n" ); document.write( "
Algebra.Com's Answer #832590 by math_tutor2020(3817)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Angle alpha is on the interval ]pi/2, pi[ which is equivalent to saying pi/2 < alpha < pi \n" ); document.write( "Each endpoint is excluded. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Because pi/2 < alpha < pi, this angle is in quadrant Q2, which is in the northwest corner.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "In Q2 we have these facts: \n" ); document.write( "cosine is negative \n" ); document.write( "sine is positive \n" ); document.write( "tangent is negative\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cos(alpha) = -12/13 = adjacent/hypotenuse \n" ); document.write( "adjacent = -12 \n" ); document.write( "hypotenuse = 13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Use the pythagorean theorem to find the opposite side is 5 units long.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "opposite = 5 \n" ); document.write( "adjacent = -12 \n" ); document.write( "hypotenuse = 13\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Then, \n" ); document.write( "sin(alpha) = opposite/hypotenuse \n" ); document.write( "sin(alpha) = 5/13 \n" ); document.write( "and \n" ); document.write( "tan(alpha) = opposite/adjacent \n" ); document.write( "tan(alpha) = 5/(-12) \n" ); document.write( "tan(alpha) = -5/12\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Diagram: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |