document.write( "Question 1198912: A weather forecast for Wednesday says that the probability of snow is 0.8, the probability for hail is 0.5, and the probability of both snow and hail is 0.3.\r
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Algebra.Com's Answer #832572 by ikleyn(52795)\"\" \"About 
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\n" ); document.write( "A weather forecast for Wednesday says that the probability of snow is 0.8,
\n" ); document.write( "the probability for hail is 0.5, and the probability of both snow and hail is 0.3.
\n" ); document.write( "According to the forecast, which of the following is an accurate conclusion?
\n" ); document.write( "A) the events of snow and hail are independent
\n" ); document.write( "B) the events of snow and hail are disjoint
\n" ); document.write( "C) either snow or hail will definitely occur
\n" ); document.write( "D) the events of snow and hail are complementary
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document.write( "(A)  They are not independent since \r\n" );
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document.write( "          P(snowing & hailing) = 0.3 =/= P(snowing)*P(hailing) = 0.8*0.5 = 0.4.\r\n" );
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document.write( "(B)  The events of snow and hail are NOT disjoint, since the probability of the intersection is not zero.\r\n" );
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document.write( "(C)  Either snow or hail will definitely occur: YES, correct, since the sum\r\n" );
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document.write( "         P(snowing OR hailing) = P(snowing) + P(hailing - P(both) = 0.8 + 0.5 - 0.3  is 1.0.\r\n" );
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document.write( "(D)  The events of snow and hail are NOT complementary, since the sum of probabilities\r\n" );
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document.write( "         P(snowing) + P(hailing) = 0.8 + 0.5 = 1.3  is not equal to 1.\r\n" );
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