document.write( "Question 114448: Please Help.\r
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\n" ); document.write( "JMS
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Algebra.Com's Answer #83256 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
If the sum of two numbers is 40, then we have the equation \"x%2By=40\" and their difference is 10 then we get another equation \"x-y=10\"\r
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Solved by pluggable solver: Solving a linear system of equations by subsitution

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=40\"
\n" ); document.write( " \"1%2Ax-1%2Ay=10\"
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\n" ); document.write( " Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.
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\n" ); document.write( " Solve for y for the first equation
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\n" ); document.write( " \"1%2Ay=40-1%2Ax\"Subtract \"1%2Ax\" from both sides
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\n" ); document.write( " \"y=%2840-1%2Ax%29\" Divide both sides by 1.
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\n" ); document.write( " Which breaks down and reduces to
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\n" ); document.write( " \"y=40-1%2Ax\" Now we've fully isolated y
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\n" ); document.write( " Since y equals \"40-1%2Ax\" we can substitute the expression \"40-1%2Ax\" into y of the 2nd equation. This will eliminate y so we can solve for x.
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\n" ); document.write( " \"1%2Ax%2B-1%2Ahighlight%28%2840-1%2Ax%29%29=10\" Replace y with \"40-1%2Ax\". Since this eliminates y, we can now solve for x.
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\n" ); document.write( " \"1%2Ax-1%2A%2840%29-1%28-1%29x=10\" Distribute -1 to \"40-1%2Ax\"
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\n" ); document.write( " \"1%2Ax-40%2B1%2Ax=10\" Multiply
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\n" ); document.write( " \"1%2Ax-40%2B1%2Ax=10\" Reduce any fractions
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\n" ); document.write( " \"1%2Ax%2B1%2Ax=10%2B40\"Add \"40\" to both sides
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\n" ); document.write( " \"1%2Ax%2B1%2Ax=50\" Combine the terms on the right side
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\n" ); document.write( " \"2%2Ax=50\" Now combine the terms on the left side.
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\n" ); document.write( " \"cross%28%281%2F2%29%282%2F1%29%29x=%2850%2F1%29%281%2F2%29\" Multiply both sides by \"1%2F2\". This will cancel out \"2%2F1\" and isolate x
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\n" ); document.write( " So when we multiply \"50%2F1\" and \"1%2F2\" (and simplify) we get
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\n" ); document.write( " \"x=25\" <---------------------------------One answer
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\n" ); document.write( " Now that we know that \"x=25\", lets substitute that in for x to solve for y
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\n" ); document.write( " \"1%2825%29-1%2Ay=10\" Plug in \"x=25\" into the 2nd equation
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\n" ); document.write( " \"25-1%2Ay=10\" Multiply
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\n" ); document.write( " \"-1%2Ay=10-25\"Subtract \"25\" from both sides
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\n" ); document.write( " \"-1%2Ay=-15\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F-1%29%28-1%29%29%2Ay=%28-15%2F1%29%281%2F-1%29\" Multiply both sides by \"1%2F-1\". This will cancel out -1 on the left side.
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\n" ); document.write( " \"y=-15%2F-1\" Multiply the terms on the right side
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\n" ); document.write( " \"y=15\" Reduce
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\n" ); document.write( " So this is the other answer
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\n" ); document.write( " \"y=15\"<---------------------------------Other answer
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\n" ); document.write( " So our solution is
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\n" ); document.write( " \"x=25\" and \"y=15\"
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\n" ); document.write( " which can also look like
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\n" ); document.write( " (\"25\",\"15\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=40\"
\n" ); document.write( " \"1%2Ax-1%2Ay=10\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"1%2Ax%2B1%2Ay=40\" (red) and \"1%2Ax-1%2Ay=10\" (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.
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\n" ); document.write( " and we can see that the two equations intersect at (\"25\",\"15\"). This verifies our answer.
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\n" ); document.write( " Plug in (\"25\",\"15\") into the system of equations
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\n" ); document.write( " Let \"x=25\" and \"y=15\". Now plug those values into the equation \"1%2Ax%2B1%2Ay=40\"
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\n" ); document.write( " \"1%2A%2825%29%2B1%2A%2815%29=40\" Plug in \"x=25\" and \"y=15\"
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\n" ); document.write( " \"25%2B15=40\" Multiply
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\n" ); document.write( " \"40=40\" Add
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\n" ); document.write( " \"40=40\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"25\",\"15\") satisfies \"1%2Ax%2B1%2Ay=40\"
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\n" ); document.write( " Let \"x=25\" and \"y=15\". Now plug those values into the equation \"1%2Ax-1%2Ay=10\"
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\n" ); document.write( " \"1%2A%2825%29-1%2A%2815%29=10\" Plug in \"x=25\" and \"y=15\"
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\n" ); document.write( " \"25-15=10\" Multiply
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\n" ); document.write( " \"10=10\" Add
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\n" ); document.write( " \"10=10\" Reduce. Since this equation is true the solution works.
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\n" ); document.write( " So the solution (\"25\",\"15\") satisfies \"1%2Ax-1%2Ay=10\"
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\n" ); document.write( " Since the solution (\"25\",\"15\") satisfies the system of equations
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\n" ); document.write( " \"1%2Ax%2B1%2Ay=40\"
\n" ); document.write( " \"1%2Ax-1%2Ay=10\"
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\n" ); document.write( " this verifies our answer.
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