document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198858>Question 1198858</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A number is divided into two parts, such that one part is 12 more than the other. If the two parts are in the ratio 4 : 3, find the number and the two parts.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #832527 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=832527\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The two parts are in the ratio 4:3, so represent the two numbers with 4x and 3x.<br><BR>\n" );
document.write( "The difference between the two numbers is 12:<br><BR>\n" );
document.write( "4x-3x=12<BR>\n" );
document.write( "x=12<br><BR>\n" );
document.write( "Then the two numbers are 4x=48 and 3x=36; the sum is 84.<br><BR>\n" );
document.write( "ANSWERS: 84, 48, and 36<br><BR>\n" );
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