document.write( "Question 1198864: For what value of k does the following system have infinitely many solutions?
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document.write( "kx + y + z=0
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document.write( "x + 2y + kz = 0
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document.write( "-X+3z=0 \n" );
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Algebra.Com's Answer #832522 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Solve the 3rd equation for z and substitute in the other two equations. \n" ); document.write( "x = 3z \n" ); document.write( "3kz+y+z=0 \n" ); document.write( "3z+2y+kz=0 \n" ); document.write( "y+(3k+1)z=0 \n" ); document.write( "2y+(3+k)z=0 \n" ); document.write( "There are infinitely many solutions if the two equations are equivalent. \n" ); document.write( "2y+(6k+2)z=0 \n" ); document.write( "2y+(3+k)z=0 \n" ); document.write( "6k+2=3+k \n" ); document.write( "5k=1 \n" ); document.write( "k=1/5 \n" ); document.write( "ANSWER: k=1/5 \n" ); document.write( " \n" ); document.write( " |