document.write( "Question 1198855: A number is divided into two parts, such that one part is 12 more than the other. If the two parts are in the ratio 4 : 3, find the number and the two parts. \n" ); document.write( "

Algebra.Com's Answer #832514 by ikleyn(52794) $\"\"$ $\"About$

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\n" ); document.write( "A number is divided into two parts, such that one part is 12 more than the other.
\n" ); document.write( "If the two parts are in the ratio 4 : 3, find the number and the two parts.
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document.write( "From the problem, the parts are 4x and 3x, where x is some common measure, now unknown.\r\n" );
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document.write( "We also are given that\r\n" );
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document.write( "    4x - 3x = 12.\r\n" );
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document.write( "It gives us x = 12, so the parts are 4*12 = 48 and 3*12 = 36.\r\n" );
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document.write( "Thus the number is 48+36 = 84 and the parts are 48 and 36.    ANSWER\r\n" );
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