document.write( "Question 1198858: A number is divided into two parts, such that one part is 12 more than the other. If the two parts are in the ratio 4 : 3, find the number and the two parts.
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Algebra.Com's Answer #832506 by Theo(13342)\"\" \"About 
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let one part be x + 12
\n" ); document.write( "let the other part be x.
\n" ); document.write( "your ratio becomes:
\n" ); document.write( "(x + 12) / x = 4/3
\n" ); document.write( "cross multiply to get:
\n" ); document.write( "4x = 3 * (x + 12)
\n" ); document.write( "simplify to get:
\n" ); document.write( "4x = 3x + 36
\n" ); document.write( "subtract 3x from both ides of the equation to get:
\n" ); document.write( "x = 36\r
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\n" ); document.write( "\n" ); document.write( "your solution is:
\n" ); document.write( "the number is equal to 36
\n" ); document.write( "the first part is 48.
\n" ); document.write( "the second part is 36.\r
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\n" ); document.write( "\n" ); document.write( "confirm your solution is correct by doing the following:
\n" ); document.write( "the ratio is 48/36 = 4/3
\n" ); document.write( "cross multiply to get:
\n" ); document.write( "4 * 36 = 3 * 48
\n" ); document.write( "simplify to get:
\n" ); document.write( "144 = 144
\n" ); document.write( "this confirms the solution is correct. \n" ); document.write( "
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