document.write( "Question 114336: Can someone direct me:\r
\n" ); document.write( "\n" ); document.write( "5x^2 = 100\r
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Algebra.Com's Answer #83250 by solver91311(24713)\"\" \"About 
You can put this solution on YOUR website!
I presume you want to solve \"5x%5E2=100\" for x.\r
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\n" ); document.write( "\n" ); document.write( "Step 1: Divide by 5\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E2=20\"\r
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\n" ); document.write( "\n" ); document.write( "Step 2: Take the square root of both sides, remembering to consider both the positive and negative square root.\r
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\n" ); document.write( "\n" ); document.write( "\"sqrt%28x%5E2%29=sqrt%2820%29\" and \"sqrt%28x%5E2%29=-sqrt%2820%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"x=2sqrt%285%29\" and \"x=-2sqrt%285%29\"
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