document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198840>Question 1198840</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the circle, the area of sector OAB is 4/3 π cm². The area of the shaded region, in cm² , is?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #832497 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=832497\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "The area of sector OAB is (4/3)pi cm^2.<br><BR>\n" );
document.write( "Angle AOB is 120 degrees, so the sector is 1/3 of the circle.<br><BR>\n" );
document.write( "So the area of the whole circle is 4pi cm^2; so the radius of the circle is 2 cm.<br><BR>\n" );
document.write( "Triangles ADC and BDO are congruent, so the shaded area is the same as the area of sector COB.<br><BR>\n" );
document.write( "The area of sector COB is half the area of sector OAB, which is given as being (4/3)pi cm^2.<br><BR>\n" );
document.write( "ANSWER: (2/3)pi cm^2<br><BR>\n" );
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