document.write( "Question 1198773: Express the following as a single logarithm of base a\r
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document.write( "2 log a(x+1)-log a(4) \r
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Algebra.Com's Answer #832419 by Theo(13342)![]() ![]() You can put this solution on YOUR website! loga(x + 1) - loga(4) is equal to loga((x+1)/4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when a = 10, you get log10(x+1) - log10(4) = log10((x+1)/4) which is equal to log((x+1)/4) on your calculator.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "to confirm, get the result of log(x+1) - log(4) and then compare it to the result of log((x+1)/4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they should be the same.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "take any random value of x that will give you a real answer. \n" ); document.write( "x = 27 will do. \n" ); document.write( "log(28) - log(4) = .84509804 \n" ); document.write( "log(28/4) = log(7) = the same.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this confirms that loga(x+1) - loga(4) is equivalent to loga((x+1)/4)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |