document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198772>Question 1198772</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Freddy is 3 years older than 6 times his grandson's age. The sum of their ages is greater than 67. What is the youngest age Freddy's grandson can be? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #832418 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=832418\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let x = freddy's age.<BR>\n" );
document.write( "let y = his grandson's age.\r<BR>\n" );
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document.write( "you have an equation and an inequality.\r<BR>\n" );
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document.write( "the equation is x = 6y + 3\r<BR>\n" );
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document.write( "the inequality is x + y > 67\r<BR>\n" );
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document.write( "replace x with 6y + 3 in the inequality to get:<BR>\n" );
document.write( "6y + 3 + y > 67<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "7y + 3 > 67<BR>\n" );
document.write( "subtract 3 from both sides of the inequality to get:<BR>\n" );
document.write( "7y > 64<BR>\n" );
document.write( "solve for y to get:<BR>\n" );
document.write( "y > 64/7\r<BR>\n" );
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document.write( "that should be your solution.<BR>\n" );
document.write( "you have to solve the equation and the inequality simultaneously.<BR>\n" );
document.write( "the common solution is when y > 64/7.\r<BR>\n" );
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document.write( "when y > 64/7, x = 6y + 3 will be greater than 405/7 and x + y will be greater than 67.\r<BR>\n" );
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document.write( "the solution appears to be that y > 64/7.\r<BR>\n" );
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document.write( "the youngest freddy's grandson can be is some amount of age greater than 64/7 years.<BR>\n" );
document.write( "it can not be 64/7 because then x = 6y + 3 would become x = 405/7 and 405/7 + 64/7 would be equal to 67 which is not allowed because x + y must be greater than 67.\r<BR>\n" );
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document.write( "y > 64/7 appears to be your solution.<BR>\n" );
document.write( "that means that the grandson's age has to be greater than 64/7\r<BR>\n" );
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document.write( "it can also be shown as y > 9 + 1/7<BR>\n" );
document.write( "it can also be shown as y > 9.142857143, depending on how many digits your calculator can display.\r<BR>\n" );
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document.write( "that's what i get.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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