document.write( "Question 1198509: Solve the system of equations.
\n" ); document.write( "X-2y+z=-3
\n" ); document.write( "-x+4y=10
\n" ); document.write( "2x-y+6z=7\r
\n" ); document.write( "\n" ); document.write( "The correct answer is one of the following. Which one?\r
\n" ); document.write( "\n" ); document.write( "A) no solution
\n" ); document.write( "B) x=2, y=3, z=1
\n" ); document.write( "C) x=-1, y=4,z=2
\n" ); document.write( "D) x=3, y=2, z=-1
\n" ); document.write( "E) x=-2, y=3, z=-4
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #832412 by MathTherapy(10552)\"\" \"About 
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\n" ); document.write( "Solve the system of equations.
\n" ); document.write( "X-2y+z=-3
\n" ); document.write( "-x+4y=10
\n" ); document.write( "2x-y+6z=7\r
\n" ); document.write( "\n" ); document.write( "The correct answer is one of the following. Which one?\r
\n" ); document.write( "\n" ); document.write( "A) no solution
\n" ); document.write( "B) x=2, y=3, z=1
\n" ); document.write( "C) x=-1, y=4,z=2
\n" ); document.write( "D) x=3, y=2, z=-1
\n" ); document.write( "E) x=-2, y=3, z=-4
\n" ); document.write( "
   x - 2y + z = - 3 ---- eq (i)\r\n" );
document.write( " - x + 4y     =  10 ---- eq (ii)\r\n" );
document.write( "  2x - y + 6z =  7 ----- eq (iii)\r\n" );
document.write( "       2y + z = 7 ------ Adding eqs (i) & (ii) ----- eq (iv)\r\n" );
document.write( "\r\n" );
document.write( " 2x - 4y + 2z = - 6 ----- Multiplying eq (i) by 2 ---- eq (v)\r\n" );
document.write( "      3y + 4z = 13 ------ Subtracting eq (v) from eq (iii) ---- eq (vi)\r\n" );
document.write( "      8y + 4z = 28 ------ Multiplying eq (iv) by 4 ---- eq (vii)\r\n" );
document.write( "           5y = 15 ------ Subtracting eq (vi) from eq (vii)\r\n" );
document.write( "           \r\n" );
document.write( "At this point, it's quite clear that it's either CHOICE B) or E).\r\n" );
document.write( "       2(3) + z = 7 ------ Substituting 3 for y in eq (iv)\r\n" );
document.write( "              z = 7 - 6 = 1 \r\n" );
document.write( "Now that we've found that y = 3, and z = 1, there's NO DOUBT that CHOICE B) is correct.\r\n" );
document.write( "\r\n" );
document.write( "If you wish, you can still continue on to determine the value of x - although it's not necessary - by substituting\r\n" );
document.write( "3 for y in eq (ii), and solving for x. This way however, you will be 100% certain that CHOICE B) is indeed correct.
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