document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198709>Question 1198709</A>: <I><SPAN STYLE=\"word-break: break-all;\"> With two reapers operating, a field can be harvested in 1 h. If only the newer reaper is used, the crop can be harvested in 1.5 h. How long would it take to harvest the field using only the older reaper? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #832351 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=832351\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "You have two different responses that show two different ways to solve \"working together\" problems like this.  Here is a third method.<br><BR>\n" );
document.write( "Consider the least common multiple of the two given times, which is 3 hours.<br><BR>\n" );
document.write( "The two reapers together harvest the field in 1 hour; so in 3 hours, the two reapers together could harvest a field that size 3/1 = 3 times.<BR>\n" );
document.write( "The newer reaper can harvest the field in 1.5 hours; so in 3 hours, the newer reaper could harvest a field that size 3/1.5 = 2 times.<BR>\n" );
document.write( "So in 3 hours, the older reaper could harvest a field that size 3-2 = 1 time.<br><BR>\n" );
document.write( "So it would take the older reaper 3 hours to harvest the field.<br><BR>\n" );
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