document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198713>Question 1198713</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that T varies directly as S, and T = 36 when S = 9, find T when S = 2. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #832350 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13203)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=832350\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Both of the responses you have received to now solve the problem by finding the constant of variation.  That is useful if you are developing a formula that you are going to use multiple times with different data.<br><BR>\n" );
document.write( "But it is more work than is necessary if you only need to find the answer to a single problem like this.<br><BR>\n" );
document.write( "The value of S changes from 9 to 2 -- i.e., it gets multiplied by a factor of 2/9.<BR>\n" );
document.write( "Since the variation is direct, T also gets multiplied by a factor of 2/9.<br><BR>\n" );
document.write( "ANSWER: 36*(2/9) = 8<br><BR>\n" );
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