document.write( "Question 1198709: With two reapers operating, a field can be harvested in 1 h. If only the newer reaper is used, the crop can be harvested in 1.5 h. How long would it take to harvest the field using only the older reaper? \n" ); document.write( "
Algebra.Com's Answer #832333 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "With two reapers operating, a field can be harvested in 1 h.
\n" ); document.write( "If only the newer reaper is used, the crop can be harvested in 1.5 h.
\n" ); document.write( "How long would it take to harvest the field using only the older reaper?
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document.write( "The combined rate of work of two reapers is \"1_field%2F1_hour\" = 1 job per hour.\r\n" );
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document.write( "The individual rate of work of the new reaper is  \r\n" );
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document.write( "    1_field/1.5_hours = \"1%2F1.5\" = \"1%2F%28%283%2F2%29%29\" = \"2%2F3\" of the job per hour.\r\n" );
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document.write( "Hence, the rate of work of the old reaper is 1 - 2/3 = 1/3 of the job per jour.\r\n" );
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document.write( "It means that the field can be harvested in 3 hours, if only old reaper is used.\r\n" );
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document.write( "ANSWER.  3 hours.\r\n" );
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