document.write( "Question 1198710: A camper drove 80 mi to a recreational area and then hiked 4 mi into the woods. The rate of the camper while driving was ten times the rate while hiking. The time spent hiking and driving was 3 h. Find the rate at which the camper hiked. \n" ); document.write( "
Algebra.Com's Answer #832332 by ikleyn(52777)\"\" \"About 
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\n" ); document.write( "A camper drove 80 mi to a recreational area and then hiked 4 mi into the woods.
\n" ); document.write( "The rate of the camper while driving was ten times the rate while hiking.
\n" ); document.write( "The time spent hiking and driving was 3 h. Find the rate at which the camper hiked.
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document.write( "Let x be the rate of hiking; 10x be the rate of driving.\r\n" );
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document.write( "The time equation is\r\n" );
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document.write( "    \"80%2F%2810x%29\" + \"4%2Fx\" = 3  hours.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    \"8%2Fx\" + \"4%2Fx\" = 3\r\n" );
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document.write( "    \"12%2Fx\" = 3\r\n" );
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document.write( "    x = \"12%2F3\" = 4.\r\n" );
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document.write( "ANSWER.  The rate of hiking is 4 miles per hour.  The rate of driving is 40 miles per hour.\r\n" );
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