document.write( "Question 1198693: Hi, I need help with this please.
\n" ); document.write( "The value of China’s exports of automobiles and parts (in billions of dollars) is approximately f(x) =1.8208_e^0.3387x, where x=0 corresponds to 1998. In what year did/will the exports reach $6.4 billion?
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Algebra.Com's Answer #832322 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=1.8208%2Ae%5E%280.3387x%29\", where \"x=0\" corresponds to \"1998\". \r
\n" ); document.write( "\n" ); document.write( "In what year did/will the exports reach $\"6.4\" billion?\r
\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=6.4\"\r
\n" ); document.write( "\n" ); document.write( "\"6.4=1.8208%2Ae%5E%280.3387x%29\"..........take natural log of both sides\r
\n" ); document.write( "\n" ); document.write( "\"ln%286.4%29=ln%281.8208%2Ae%5E%280.3387x%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%286.4%29=ln%281.8208%29%2Bln%28e%5E%280.3387x%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%286.4%29-ln%281.8208%29=%280.3387x%29ln%28e%29\"...........\"ln%28e%29=1\"\r
\n" ); document.write( "\n" ); document.write( "\"ln%286.4%29-ln%281.8208%29=0.3387x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=%28ln%286.4%29-ln%281.8208%29%29%2F0.3387\"\r
\n" ); document.write( "\n" ); document.write( "\"x=3.71131\"years \r
\n" ); document.write( "\n" ); document.write( "\"x=3\" years \"8\" months \"16\" days\r
\n" ); document.write( "\n" ); document.write( "if \"x=0\" corresponds to \"1998\", then\r
\n" ); document.write( "\n" ); document.write( "\"x=3.71131\" corresponds to \"1998%2B3\"years \"8\" months \"16\" days\r
\n" ); document.write( "\n" ); document.write( "\"2001\"year \"8\" months \"16\" days\r
\n" ); document.write( "\n" ); document.write( " the exports will reach $\"6.4\" billion in \"2001\"\r
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