document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198657>Question 1198657</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Evaluate tan(-240 degrees(\r<BR>\n" );
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document.write( "The correct answer is one of the following.  Which one?\r<BR>\n" );
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document.write( "A) 1/2\r<BR>\n" );
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document.write( "B) (square root of 2)/2\r<BR>\n" );
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document.write( "C) - (square root of 3)\r<BR>\n" );
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document.write( "D) - (square root of2)/2\r<BR>\n" );
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document.write( "E) (square root of 3)/2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #832274 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=832274\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> tan(-240) = - 1.732050808, according to my calculator.\r<BR>\n" );
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document.write( "without a calculator, i would probably do the following:\r<BR>\n" );
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document.write( "add 360 to -240 to get 120 degrees.<BR>\n" );
document.write( "the equivalent angle in the first quadrant is 180 minus 120 = 60 degrees.<BR>\n" );
document.write( "tan(60) = (sqrt(3)/2)/(1/2) = sqrt(3).<BR>\n" );
document.write( "tangent in the second quadrant is negative, so tan(120) = -sqrt(3).<BR>\n" );
document.write( "using my calculator, i find that -sqrt(3) = - 1.732050808.<BR>\n" );
document.write( "this is  the same i got using my calculator directly on -240 degrees.\r<BR>\n" );
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document.write( "solution is therefore -sqrt(3) which is equal to selection C.\r<BR>\n" );
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document.write( "if you graph tan(-240), you will find the same answer, as shown below:\r<BR>\n" );
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document.write( " </SPAN>\n" );
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