document.write( "Question 1198616: The width of a rectangle is the length minus 6 units. The area of the rectangle is 27 units. What is the length and width of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #832242 by Theo(13342)\"\" \"About 
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A = area
\n" ); document.write( "L = length
\n" ); document.write( "W = width\r
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\n" ); document.write( "\n" ); document.write( "A = L * W
\n" ); document.write( "W = L - 6
\n" ); document.write( "A = L * (L - 6)\r
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\n" ); document.write( "\n" ); document.write( "A = 27
\n" ); document.write( "27 = L * (L - 6)
\n" ); document.write( "L * (L - 6) = L^2 - 6L
\n" ); document.write( "27 = L^2 - 6L
\n" ); document.write( "subtract 27 from both sides of that equation to get:
\n" ); document.write( "L^2 - 6L - 27 = 0
\n" ); document.write( "factor that quadratic equation to get:
\n" ); document.write( "(L - 9) * (L + 3) = 0
\n" ); document.write( "L = 9 or L = -3.
\n" ); document.write( "L can't be -3, so L = 9
\n" ); document.write( "W = L - 6 makes W = 3\r
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\n" ); document.write( "\n" ); document.write( "dimensions are:
\n" ); document.write( "L = 9
\n" ); document.write( "W = 3
\n" ); document.write( "A = L * W = 9 * 3 = 27\r
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\n" ); document.write( "\n" ); document.write( "length of the rectangle is 9 units and width of the rectangle is 3 units.
\n" ); document.write( "that's your solution.\r
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\n" ); document.write( "\n" ); document.write( "requirements of the problem are solved, since length of 9 units minus 6 units is equal to 3 units which is the width.\r
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