document.write( "Question 1198424: Cynthia Besch wants to buy a rug for a room that is 22 ft wide and 30 ft long. She wants to leave a uniform strip of floor around the rug. She can afford to buy 560 square feet of carpeting. What dimensions should the rug​ have? \n" ); document.write( "
Algebra.Com's Answer #832179 by MathTherapy(10551)\"\" \"About 
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Cynthia Besch wants to buy a rug for a room that is 22 ft wide and 30 ft long. She wants to leave a uniform strip of floor around the rug. She can afford to buy 560 square feet of carpeting. What dimensions should the rug​ have?
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Let the width of the uniform strip be W\r\n" );
document.write( "With dimensions of the room being 22 ft by 30 ft, dimensions of the rug will be 22 - 2W, and 30 - 2W\r\n" );
document.write( "We then get the following RUG-AREA equation: (22 - 2W)(30 - 2W) = 560 \r\n" );
document.write( "                                             2(11 - W)2(15 - W) = 2(2)(140) ------ Factoring out 2(2), or 4 on each side\r\n" );
document.write( "                                               (11 - W)(15 - W) = 140\r\n" );
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document.write( "                                                (W - 1)(W - 25) = 0 --- Factoring trinomial\r\n" );
document.write( "                                                 W - 1 = 0     OR       W - 25 = 0\r\n" );
document.write( "Width of unifrom strip, or W = 1       or      W = 25 (ignore, as width of strip CANNOT be > the room's width or length)\r\n" );
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document.write( "With width (W) of strip being 1 foot, dimensions of rug are: 22 - 2(1) by 30 - 2(1) = 20 ft by 28 ft.\r\n" );
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document.write( "** NOTE: You don't need to use the quadratic equation formula as the other person did. Too much work, too much time,\r\n" );
document.write( "         and DEFINITELY too many large numbers, which can make one, prone to errors!!
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