document.write( "Question 114401: The sum of two areas of two circles is 128(pie)ft^2. The difference of the circumferences is 8(pie)ft. Find the radius of each circle. \n" ); document.write( "
Algebra.Com's Answer #83217 by stanbon(75887)\"\" \"About 
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The sum of two areas of two circles is 128(pie)ft^2. The difference of the circumferences is 8(pie)ft. Find the radius of each circle.
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\n" ); document.write( "Let the respective radii be \"r\" and \"R\"
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\n" ); document.write( "EQUATIONS:
\n" ); document.write( "(pi)r^2 + pi(R)^2 = 128pi
\n" ); document.write( "2pir - 2piR = 8pi
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\n" ); document.write( "Simplify:
\n" ); document.write( "r^2 + R^2 = 128
\n" ); document.write( "r - R = 4
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\n" ); document.write( "Substitute:
\n" ); document.write( "(R+4)^2 + R^2 = 128
\n" ); document.write( "2R^2 + 8R + 16 = 128\r
\n" ); document.write( "\n" ); document.write( "2R^2 + 8R - 112 = 0
\n" ); document.write( "R^2 + 4R - 56 = 0
\n" ); document.write( "R = [-4 +- sqrt(16-4*-56)]/2\r
\n" ); document.write( "\n" ); document.write( "R = [-4 +- sqrt(240)]/2\r
\n" ); document.write( "\n" ); document.write( "R = [-4 + sqrt(240)]/2 = 5.745966692...
\n" ); document.write( "r = 4+R = 9.745966692...
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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