document.write( "Question 114401: The sum of two areas of two circles is 128(pie)ft^2. The difference of the circumferences is 8(pie)ft. Find the radius of each circle. \n" ); document.write( "
Algebra.Com's Answer #83217 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The sum of two areas of two circles is 128(pie)ft^2. The difference of the circumferences is 8(pie)ft. Find the radius of each circle. \n" ); document.write( "---------------- \n" ); document.write( "Let the respective radii be \"r\" and \"R\" \n" ); document.write( "------------------------------------------ \n" ); document.write( "EQUATIONS: \n" ); document.write( "(pi)r^2 + pi(R)^2 = 128pi \n" ); document.write( "2pir - 2piR = 8pi \n" ); document.write( "------------------------- \n" ); document.write( "Simplify: \n" ); document.write( "r^2 + R^2 = 128 \n" ); document.write( "r - R = 4 \n" ); document.write( "----------------- \n" ); document.write( "Substitute: \n" ); document.write( "(R+4)^2 + R^2 = 128 \n" ); document.write( "2R^2 + 8R + 16 = 128\r \n" ); document.write( "\n" ); document.write( "2R^2 + 8R - 112 = 0 \n" ); document.write( "R^2 + 4R - 56 = 0 \n" ); document.write( "R = [-4 +- sqrt(16-4*-56)]/2\r \n" ); document.write( "\n" ); document.write( "R = [-4 +- sqrt(240)]/2\r \n" ); document.write( "\n" ); document.write( "R = [-4 + sqrt(240)]/2 = 5.745966692... \n" ); document.write( "r = 4+R = 9.745966692... \n" ); document.write( "================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |