document.write( "Question 1198341: Given that $\"+a+%2B++1%2F%28+b%2B2%2Fc+%29+=+17%2F5++\"$ , where a is the integer part of the mixed number, and c is the numerator of the fraction part of the mixed number when the mixed number is written in the least terms, find the product abc.\r
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Algebra.Com's Answer #832048 by MathTherapy(10552) $\"\"$ $\"About$

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Given that $\"+a+%2B++1%2F%28+b%2B2%2Fc+%29+=+17%2F5++\"$ , where a is the integer part of the mixed number, and c is the numerator of the fraction part of the mixed number when the mixed number is written in the least terms, find the product abc.\r
\n" ); document.write( "\n" ); document.write( "A) 9
\n" ); document.write( "B) 18
\n" ); document.write( "C) 6
\n" ); document.write( "D) 30
\n" ); document.write( "E) 3
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document.write( "We see clearly that a = 3 \r\n" );
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document.write( "In addition, since c is the numerator of the reduced fraction in the mixed number, then c = 2\r\n" );
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document.write( "Now, we need to change the 2 in the numerator in the mixed number on the right () to MATCH\r\n" );
document.write( "the 1 in the numerator in the mixed number on the left .\r\n" );
document.write( "How do we achieve that? \r\n" );
document.write( "We simply divide the 2 in the numerator in the mixed number on the right by 2 to get 1. We then do the same to the \r\n" );
document.write( "denominator (divide it by 2), as follows: \r\n" );
document.write( "                                       We now see that:  \r\n" );
document.write( "                                                         ---- Substituting 2 for c\r\n" );
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document.write( "                                                         5 = 2b + 2 --- Denominators are equal and so are the numerators\r\n" );
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document.write( "                                      With , we finally get: \r\n" );
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document.write( "CHECK\r\n" );
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