document.write( "Question 1198443: A movie theater has a seating capacity of 151. The theater charges $5.00 for children, $7.00 for students, and $12.00 for adults. There are half as many adults as there are children. If the total ticket sales was $ 1084, How many children, students, and adults attended?
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Algebra.Com's Answer #832035 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "A movie theater has a seating capacity of 151.
\n" ); document.write( "The theater charges $5.00 for children, $7.00 for students, and $12.00 for adults.
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document.write( "x adults, 2x children and the rest (151-x-2x) = (151-3x) are the students.\r\n" );
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document.write( "Write the total money equation\r\n" );
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document.write( "    12x + 5*(2x) + 7*(151-3x) = 1084.\r\n" );
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document.write( "Simplify and find x\r\n" );
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document.write( "    12x + 10x + 7*151 - 21x = 1084\r\n" );
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document.write( "           x               = 1084 - 7*151 = 27.\r\n" );
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document.write( "ANSWER.  27 adults, 54 children and the rest 151-27-54 = 70 are students.\r\n" );
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\n" ); document.write( "\n" ); document.write( "Three unknown are found using one equation, which is a kind of miracle.\r
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