document.write( "Question 1198442: S3.25 in dimes and nickels, were distributed among 45 boys. If each received
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document.write( "one coin, how many received dimes and how many received nickels? \n" );
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Algebra.Com's Answer #832028 by Theo(13342)![]() ![]() You can put this solution on YOUR website! x = number of dimes \n" ); document.write( "y = number of nickels \n" ); document.write( "x + y = 45 \n" ); document.write( ".1x + .05y = 3.25 \n" ); document.write( "those are your two equations that need to be solved simultaneously. \n" ); document.write( "multiply both sides of the first equation by .1 and leave the second equation as is to get: \n" ); document.write( ".1x + .1y = 4.50 \n" ); document.write( ".1x + .05y = 3.25 \n" ); document.write( "subtract the second equation from the first to get: \n" ); document.write( ".05y = 1.25 \n" ); document.write( "solve for y to get: \n" ); document.write( "y = 25 \n" ); document.write( "this makes x = 20 because x + y = 45 \n" ); document.write( "you have: \n" ); document.write( "20 dimes and 25 nickels. \n" ); document.write( "the total value is 20 * .10 + 25 * .05 = 2.00 + 1.25 = 3.25. \n" ); document.write( "your solution is: \n" ); document.write( "20 received 1 dime each and 25 received 1 nickel each. \n" ); document.write( " \n" ); document.write( " |