document.write( "Question 1198427: The width of a rectangle is 3 less than twice it’s length if the area of the rectangle is 47 cm^2 what is the length of the diagonal \n" ); document.write( "
Algebra.Com's Answer #832017 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "The width of a rectangle is \"3\" less than twice it’s length\r
\n" ); document.write( "\n" ); document.write( "\"W=2L-3\"------eq1\r
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\n" ); document.write( "\n" ); document.write( "\"A=+47cm%5E2\"\r
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\n" ); document.write( "\n" ); document.write( "\"A=L%2AW\"---- substitute \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"A=L%2A%282L-3%29\"\r
\n" ); document.write( "\n" ); document.write( "\"47=2L%5E2-3L\"\r
\n" ); document.write( "\n" ); document.write( "\"2L%5E2-3L-47=0\"\r
\n" ); document.write( "\n" ); document.write( "using quadratic formula we get\r
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\n" ); document.write( "\"L+=+3%2F4+-+sqrt%28385%29%2F4=-4.16\"\r
\n" ); document.write( "\n" ); document.write( "or\r
\n" ); document.write( "\n" ); document.write( "\"L+=+3%2F4+%2B+sqrt%28385%29%2F4=5.66\"\r
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\n" ); document.write( "\n" ); document.write( "We obviously only want the second answer.\r
\n" ); document.write( "\n" ); document.write( "go to eq1\r
\n" ); document.write( "\n" ); document.write( "\"W=2%2A5.66-3\"\r
\n" ); document.write( "\n" ); document.write( "\"W=8.32\"\r
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\n" ); document.write( "\n" ); document.write( "diagonal:\r
\n" ); document.write( "\n" ); document.write( "\"d%5E2=5.66%5E2%2B8.32%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"d%5E2=101.258\"\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28101.258%29\"\r
\n" ); document.write( "\n" ); document.write( "\"d=10.06cm\"\r
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