document.write( "Question 1198349: Assume that, when a child is born, the probability it is a girl is ½ and that the sex of the child does not depend on the sex of an older sibling. Find the probability distribution for the number of girls in a family with 4 children
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Algebra.Com's Answer #831991 by math_tutor2020(3817) ![]() You can put this solution on YOUR website! \n" ); document.write( "It appears that the tutor @ewatrrr might have misread the question.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The task is to find the probability distribution for the number of girls in this family. The teacher wants a probability table showing all the possible outcomes, and associated probabilities.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Convention is to use the binomial distribution. However, I'll take a different approach.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "X = number of girls \n" ); document.write( "X ranges from X = 0 to X = 4\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The calculation @ewatrrr has provided applies to both X = 0 girls (aka 4 boys) and also X = 4 girls (0 boys) due to symmetry.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "B = boy \n" ); document.write( "G = girl\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "X = 0 girls \n" ); document.write( "BBBB\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "X = 1 girl \n" ); document.write( "BBBG \n" ); document.write( "BBGB \n" ); document.write( "BGBB \n" ); document.write( "GBBB \n" ); document.write( "There are four cases where the family has 1 girl \n" ); document.write( "We can see this using the nCr formula with n = 4 and r = 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "X = 2 girls \n" ); document.write( "BBGG \n" ); document.write( "BGGB \n" ); document.write( "BGBG \n" ); document.write( "GBBG \n" ); document.write( "GBGB \n" ); document.write( "GGBB \n" ); document.write( "There are six cases where the family has 2 girls \n" ); document.write( "This value (6) can be calculated by computing the nCr value when n = 4 and r = 2.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "X = 3 girls \n" ); document.write( "GGGB \n" ); document.write( "GGBG \n" ); document.write( "GBGG \n" ); document.write( "BGGG \n" ); document.write( "There are four cases where the family has 3 girls (notice the similar structure to the X = 1 girl case) \n" ); document.write( "This value (4) can be calculated by computing the nCr value when n = 4 and r = 3.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "X = 4 girls \n" ); document.write( "GGGG \n" ); document.write( "There is one case where the family has 3 girls (notice the similar structure to the X = 0 girls case) \n" ); document.write( "There's no need to use nCr here, but if you wanted then it would be n = 4 and r = 4.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "There are 2^4 = 16 ways to have four kids.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is the probability distribution \n" ); document.write( "
\n" ); document.write( "Thing to notice: The numerators 1,4,6,4,1 are found in the same row of Pascal's Triangle \n" ); document.write( "I decided to not reduce the fractions to keep the denominators consistent.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is what it looks like after reducing those fractions \n" ); document.write( "
\n" ); document.write( "Another thing to notice: The P(X) values add to 1. \n" ); document.write( " \n" ); document.write( " |