document.write( "Question 1198349: Assume that, when a child is born, the probability it is a girl is ½ and that the sex of the child does not depend on the sex of an older sibling. Find the probability distribution for the number of girls in a family with 4 children
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Algebra.Com's Answer #831991 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "It appears that the tutor @ewatrrr might have misread the question.\r
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\n" ); document.write( "\n" ); document.write( "The task is to find the probability distribution for the number of girls in this family. The teacher wants a probability table showing all the possible outcomes, and associated probabilities.\r
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\n" ); document.write( "\n" ); document.write( "Convention is to use the binomial distribution. However, I'll take a different approach.\r
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\n" ); document.write( "\n" ); document.write( "X = number of girls
\n" ); document.write( "X ranges from X = 0 to X = 4\r
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\n" ); document.write( "\n" ); document.write( "The calculation @ewatrrr has provided applies to both X = 0 girls (aka 4 boys) and also X = 4 girls (0 boys) due to symmetry.\r
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\n" ); document.write( "\n" ); document.write( "B = boy
\n" ); document.write( "G = girl\r
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\n" ); document.write( "\n" ); document.write( "X = 0 girls
\n" ); document.write( "BBBB\r
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\n" ); document.write( "\n" ); document.write( "X = 1 girl
\n" ); document.write( "BBBG
\n" ); document.write( "BBGB
\n" ); document.write( "BGBB
\n" ); document.write( "GBBB
\n" ); document.write( "There are four cases where the family has 1 girl
\n" ); document.write( "We can see this using the nCr formula with n = 4 and r = 1.\r
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\n" ); document.write( "\n" ); document.write( "X = 2 girls
\n" ); document.write( "BBGG
\n" ); document.write( "BGGB
\n" ); document.write( "BGBG
\n" ); document.write( "GBBG
\n" ); document.write( "GBGB
\n" ); document.write( "GGBB
\n" ); document.write( "There are six cases where the family has 2 girls
\n" ); document.write( "This value (6) can be calculated by computing the nCr value when n = 4 and r = 2.\r
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\n" ); document.write( "\n" ); document.write( "X = 3 girls
\n" ); document.write( "GGGB
\n" ); document.write( "GGBG
\n" ); document.write( "GBGG
\n" ); document.write( "BGGG
\n" ); document.write( "There are four cases where the family has 3 girls (notice the similar structure to the X = 1 girl case)
\n" ); document.write( "This value (4) can be calculated by computing the nCr value when n = 4 and r = 3.\r
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\n" ); document.write( "\n" ); document.write( "X = 4 girls
\n" ); document.write( "GGGG
\n" ); document.write( "There is one case where the family has 3 girls (notice the similar structure to the X = 0 girls case)
\n" ); document.write( "There's no need to use nCr here, but if you wanted then it would be n = 4 and r = 4.\r
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\n" ); document.write( "\n" ); document.write( "There are 2^4 = 16 ways to have four kids.\r
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\n" ); document.write( "\n" ); document.write( "This is the probability distribution
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XP(X)
01/16
14/16
26/16
34/16
41/16

\n" ); document.write( "Thing to notice: The numerators 1,4,6,4,1 are found in the same row of Pascal's Triangle
\n" ); document.write( "I decided to not reduce the fractions to keep the denominators consistent.\r
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\n" ); document.write( "\n" ); document.write( "This is what it looks like after reducing those fractions
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XP(X)
01/16
11/4
23/8
31/4
41/16

\n" ); document.write( "Another thing to notice: The P(X) values add to 1.
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