document.write( "Question 1198384: After transformations, the expression sin (A + B)sin (A - B) can be proved to be equal to:
\n" ); document.write( "A) sin^2 A - sin^2
\n" ); document.write( "B) sin A - sin B
\n" ); document.write( "C) 2 sin A sin B
\n" ); document.write( "D) 2 cos A cos B
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Algebra.Com's Answer #831963 by math_tutor2020(3817)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Answer: sin^2(A) - sin^2(B)\r
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\n" ); document.write( "\n" ); document.write( "Explanation:\r
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\n" ); document.write( "\n" ); document.write( "There are at least two methods we can follow to prove that
\n" ); document.write( "sin(A+B)sin(A-B) = sin^2(A)-sin^2(B)
\n" ); document.write( "is an identity\r
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\n" ); document.write( "\n" ); document.write( "Method 1\r
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\n" ); document.write( "\n" ); document.write( "Let
\n" ); document.write( "m = sin(A)cos(B)
\n" ); document.write( "n = cos(A)sin(B)\r
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\n" ); document.write( "\n" ); document.write( "sin(A+B)sin(A-B) = [ sin(A)cos(B)+cos(A)sin(B) ] * [ sin(A)cos(B)-cos(A)sin(B) ]
\n" ); document.write( "sin(A+B)sin(A-B) = (m+n)(m-n)
\n" ); document.write( "sin(A+B)sin(A-B) = m^2 - n^2
\n" ); document.write( "sin(A+B)sin(A-B) = (sin(A)cos(B))^2 - (cos(A)sin(B))^2
\n" ); document.write( "sin(A+B)sin(A-B) = sin^2(A)cos^2(B) - cos^2(A)sin^2(B)
\n" ); document.write( "sin(A+B)sin(A-B) = sin^2(A)(1-sin^2(B)) - (1-sin^2(A))sin^2(B)
\n" ); document.write( "sin(A+B)sin(A-B) = sin^2(A)-sin^2(A)sin^2(B) - sin^2(B)+sin^2(A)sin^2(B)
\n" ); document.write( "sin(A+B)sin(A-B) = sin^2(A) - sin^2(B)\r
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\n" ); document.write( "\n" ); document.write( "The relevant identities that I used were:
\n" ); document.write( "sin(A+B) = sin(A)cos(B)+cos(A)sin(B)
\n" ); document.write( "sin(A-B) = sin(A)cos(B)-cos(A)sin(B)
\n" ); document.write( "cos^2(A) = 1 - sin^2(A) which is from sin^2(A)+cos^2(A) = 1\r
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\n" ); document.write( "\n" ); document.write( "Method 2\r
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\n" ); document.write( "\n" ); document.write( "Another identity to use is
\n" ); document.write( "sin(u)*sin(v) = 0.5 * [ cos(u-v) - cos(u+v) ]
\n" ); document.write( "which should be somewhere on your list of trig identities.\r
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\n" ); document.write( "\n" ); document.write( "Let
\n" ); document.write( "u = A+B
\n" ); document.write( "v = A-B
\n" ); document.write( "So,
\n" ); document.write( "sin(u)*sin(v) = 0.5 * [ cos(u-v) - cos(u+v) ]
\n" ); document.write( "sin(A+B)*sin(A-B) = 0.5 * [ cos(A+B-(A-B)) - cos(A+B+A-B) ]
\n" ); document.write( "sin(A+B)*sin(A-B) = 0.5 * [ cos(2B) - cos(2A) ]
\n" ); document.write( "sin(A+B)*sin(A-B) = 0.5 * [ (1-2sin^2(B))-(1-2sin^2(A)) ]
\n" ); document.write( "sin(A+B)*sin(A-B) = 0.5 * [ 1-2sin^2(B)-1+2sin^2(A) ]
\n" ); document.write( "sin(A+B)*sin(A-B) = 0.5 * [ -2sin^2(B)+2sin^2(A) ]
\n" ); document.write( "sin(A+B)*sin(A-B) = 0.5 * [ 2sin^2(A)-2sin^2(B) ]
\n" ); document.write( "sin(A+B)*sin(A-B) = sin^2(A)-sin^2(B)\r
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\n" ); document.write( "\n" ); document.write( "Edit:
\n" ); document.write( "Here's a handy list of trig identities
\n" ); document.write( "https://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
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