document.write( "Question 1198328: You are given an unfair coin with probability of obtaining a head equal to
\n" ); document.write( "1/3, 000, 000, 000. You toss this coin 6,000,000,000 times. Let A be the
\n" ); document.write( "event that you get “tails for all the tosses”. Let B be the event that you get
\n" ); document.write( "“heads for all the tosses”.
\n" ); document.write( "i) Approximate P (A).
\n" ); document.write( "ii) Approximate P (A ∪ B)
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Algebra.Com's Answer #831933 by MathLover1(20850)\"\" \"About 
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Let \"N+\"be the number of heads among the \"n\" tosses. Then, \"N\"\"B\"(\"n\",\"+p\"). \r
\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "probability of obtaining a head equal to:\"1%2F3000000000=1%2F%283+%2A10%5E9%29\" \r
\n" ); document.write( "\n" ); document.write( "You toss this coin \"6000000000=+6%2A10%5E9\" times\r
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\n" ); document.write( "\n" ); document.write( "Here, we have small \"p+=+1%2F%283+%2A10%5E9%29\" and large \"n+=+6%2A10%5E9\". So, we can apply Poisson approximation.\r
\n" ); document.write( "\n" ); document.write( "In other words, \"B\"(\"n\",\"+p\") is well-approximated by \"P%28alpha%29\" where \"alpha+=+np+=+2\".\r
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\n" ); document.write( "\n" ); document.write( "(a) \r
\n" ); document.write( "\n" ); document.write( "\"P%28A%29\" = \"P\" [\"N+=+0\"] = \"e%5E-2%282%5E0%2F0%21%29=1%2Fe%5E2\"\"0.1353\"\r
\n" ); document.write( "\n" ); document.write( "(b) \r
\n" ); document.write( "\n" ); document.write( "\"P\"(\"A\"\"B\")= \"P\" [\"N+=+0\"]+\"P\" [\"N+=+n\"] = \"e%5E-2%282%5E0%2F0%21%29%2Be%5E-2%28%282%5E6%2A10%5E9%29%2F%286%2A10%5E9%29%21%29\"\r
\n" ); document.write( "\n" ); document.write( " The second term is \"extremely\"\"+small\" compared to the first one. \r
\n" ); document.write( "\n" ); document.write( "Hence, \"P\"(\"A\"\"B\") is approximately the same as \"P%28A%29\".\r
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