document.write( "Question 1198342: Given that \"+a+%2B+1%2F+%28b%2B2%2Fc%29+=+17%2F5+\", where a is the integer part of the mixed number, and c is the numerator of the fraction part of the mixed number when the mixed number is written in the least terms, find the product ABC.\r
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\n" ); document.write( "\n" ); document.write( "@josgarithmetic(37819), if you don't know how to answer this question, then don't say anything.
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Algebra.Com's Answer #831916 by Edwin McCravy(20056)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "\"+a+%2B+1%2F+%28b%2B2%2Fc%29+=+17%2F5+\"\r\n" );
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document.write( "Change the \"17%2F5\" to mixed number \"3%262%2F5\"\r\n" );
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document.write( "\"+a+%2B+1%2F+%28b%2B2%2Fc%29+=+3%2B2%2F5+\"\r\n" );
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document.write( "Since a is the whole part, a = 3, so subtract 'a' from the\r\n" );
document.write( "left side and '3' from the right side:\r\n" );
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document.write( "\"1%5E%22%22%2F+%28b%2B2%2Fc%29+=+2%2F5+\"\r\n" );
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document.write( "Since c is the numerator of the fraction part of the mixed number,\r\n" );
document.write( "c=2\r\n" );
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document.write( "\"1%5E%22%22%2F+%28b%2B2%2F2%29+=+2%2F5+\"\r\n" );
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document.write( "\"1%2F+%28b%2B1%29+=+2%2F5+\"\r\n" );
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document.write( "Cross-multiply:\r\n" );
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document.write( "\"5=2%28b%2B1%29\"\r\n" );
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document.write( "\"5=2b%2B2\"\r\n" );
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document.write( "\"3=2b\"\r\n" );
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document.write( "\"3%2F2=b\"\r\n" );
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document.write( "So \"a=3\", \"b=3%2F2\", \"c=2\", and \r\n" );
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document.write( "Edwin
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