document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198319>Question 1198319</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive numbers such that the sum of the first and twice the second is forty-six less than six times the third. The third number is </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #831903 by </B><A HREF=/tutors/aboutme.mpl?userid=ewatrrr><B>ewatrrr(24785)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ewatrrr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ewatrrr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=831903\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x + 2(x+1)= 6(x+2)-46***<BR>\n" );
document.write( "x + 2x + 2 = 6x + 12 - 46<BR>\n" );
document.write( "       36 = 3x<BR>\n" );
document.write( "       12 = x<BR>\n" );
document.write( "three consecutive numbers are: 12, 13, 14<BR>\n" );
document.write( "checking***: 12+26 = 6*14 -46 = 38  Checks </SPAN>\n" );
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