document.write( "Question 1198300: sin(13pi/12) cos(13pi/12) \n" ); document.write( "
Algebra.Com's Answer #831873 by ikleyn(52864)\"\" \"About 
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document.write( "    \"sin%2813pi%2F12%29%2Acos%2813pi%2F12%29\" = use the standard trigonometry identity = \r\n" );
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document.write( "  = \"%281%2F2%29%2Asin%282%2A%2813pi%2F12%29%29\" = \"%281%2F2%29%2Asin%2826pi%2F12%29\" = \"%281%2F2%29%2Asin%282pi%2F12%29\" = \"%281%2F2%29%2Asin%28pi%2F6%29\" = \"%281%2F2%29%2A%281%2F2%29\" = \"1%2F4\" = 0.25.    ANSWER\r\n" );
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