document.write( "Question 114313: decompose into a partial fraction\r
\n" ); document.write( "\n" ); document.write( "5x+7/x^2+2x-3 \n" ); document.write( "

Algebra.Com's Answer #83183 by stanbon(75887) $\"\"$ $\"About$

You can put this solution on YOUR website!
decompose into a partial fraction
\n" ); document.write( "5x+7/x^2+2x-3\r
\n" ); document.write( "\n" ); document.write( "= (5x+7)/[(x+3)(x-1)]\r
\n" ); document.write( "\n" ); document.write( "----------------------------
\n" ); document.write( "Let (5x+7)/[(x+3)(x-1)] = A/(x+3) + B/(x-1)\r
\n" ); document.write( "\n" ); document.write( "= [A(x-1)+B(x+3)]/ ...\r
\n" ); document.write( "\n" ); document.write( "= [(A+B)x +(-A+3B)]/...\r
\n" ); document.write( "\n" ); document.write( "---------------------------
\n" ); document.write( "EQUATION:
\n" ); document.write( "A+B = 5
\n" ); document.write( "-A+3B = 7
\n" ); document.write( "--------
\n" ); document.write( "Add to get:
\n" ); document.write( "4B = 12
\n" ); document.write( "B = 3
\n" ); document.write( "------------
\n" ); document.write( "Substitute to solve for A:
\n" ); document.write( "A + 3 = 5
\n" ); document.write( "A = 2
\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "
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