document.write( "Question 1198261: The base edges of a triangular pyramid are 12, 14, and 16, and its altitude is 22.
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Algebra.Com's Answer #831818 by ikleyn(52909)\"\" \"About 
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document.write( "Find the area of the triangular base. Use the Heron's formula.\r\n" );
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document.write( "The half of the perimeter of the base triangle is  s = \"%2812%2B14%2B16%29%2F2\" = \"42%2F2\" = 21.\r\n" );
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document.write( "The area of the base is  A = \"sqrt%2821%2A%2821-12%29%2A%2821-14%29%2A%2821-16%29%29\" = \"sqrt%2821%2A9%2A7%2A5%29\" = \"7%2A3%2Asqrt%2815%29\" = \"21%2Asqrt%2815%29\".\r\n" );
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document.write( "The volume of the pyramid is  \"%281%2F3%29%2AA%2A22\" = \"%281%2F3%29%2A21%2A22%2Asqrt%2815%29\" = \"7%2A22%2Asqrt%2815%29\" = \"154%2Asqrt%2815%29\".\r\n" );
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document.write( "Thus a = 154.    ANSWER\r\n" );
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\n" ); document.write( "\n" ); document.write( "On the Heron's formula,  see the lessons\r
\n" ); document.write( "\n" ); document.write( "    - Proof of the Heron's formula for the area of a triangle \r
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