document.write( "Question 1198240: How many inches long is the altitude of a regular triangular pyramid the base of which is 12 inches on a side and its volume is 103.8 cubic inches? Round off the answer to the nearest integer. \n" ); document.write( "
Algebra.Com's Answer #831808 by ewatrrr(24785)\"\" \"About 
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\n" ); document.write( "V = 1/3 bh = 103.8in^3 (b is the area of the base)
\n" ); document.write( "Given: the base of which is 12 inches on a side: b = 144in^2
\n" ); document.write( " \"%28144in%5E2%29%2Ah+=+3%28103.8in%5E++++3+%29\"
\n" ); document.write( " h = \"%28311.4in%5E3%29%2F%28144in%5E2%29\" = 2.1625in
\n" ); document.write( " 0r
\n" ); document.write( "h= 2in (nearest integer)
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