document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=17162>Question 17162</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with subtracting radicals PLEASE!!!!!!<BR>\n" );
document.write( "The problem is 5sqrt72-3sqrt48-4sqrt128= </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #8318 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=8318\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5sqrt72-3sqrt48-4sqrt128=?...the procedure is to factorise the radicals and take as much as possible out side the radical and simplify as per the classification<BR>\n" );
document.write( "for ex...sqrt72=sqrt2*2*2*3*3..there are three 2's and two 3's .so we can take two each of them out side the radical of square root,leaving only one 2 in the radical...<BR>\n" );
document.write( "sqrt72=sqrt2*2*2*3*3=2*3sqrt2=6sqrt2...similarly<BR>\n" );
document.write( "sqrt48=sqrt2*2*2*2*3=2*2sqrt3=4sqrt3<BR>\n" );
document.write( "sqrt128=sqrt2*2*2*2*2*2*2=2*2*2sqrt2=8sqrt2..<BR>\n" );
document.write( "now  you should know that in their simplest form like sqrt2,sqrt3,sqrt5...etc can not be simplified any further and can be added or subtracted within their category only..<BR>\n" );
document.write( "so we have now 5sqrt72-3sqrt48-4sqrt128=5*6sqrt2-3*4sqrt3-4*8sqrt2=sqrt2(30-32)-12sqrt3=-2sqrt2-12sqrt3...answer </SPAN>\n" );
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