document.write( "Question 1198188: the lin y=2x-10 meets the x-axis at point a. the line y=-2x+4 meets the y-axis at the point b. Find the equation of the line joining a and b\r
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Algebra.Com's Answer #831739 by math_tutor2020(3817)\"\" \"About 
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\n" ); document.write( "Plug in y = 0 and solve for x to locate the x intercept.\r
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\n" ); document.write( "\n" ); document.write( "y = 2x-10
\n" ); document.write( "0 = 2x-10
\n" ); document.write( "2x = 10
\n" ); document.write( "x = 10/2
\n" ); document.write( "x = 5
\n" ); document.write( "The x intercept is located at (5,0)
\n" ); document.write( "This is the location of point A.\r
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\n" ); document.write( "\n" ); document.write( "Now plug in x = 0 to find the y intercept for the other linear equation
\n" ); document.write( "y = -2x+4
\n" ); document.write( "y = -2(0)+4
\n" ); document.write( "y = 4
\n" ); document.write( "The y intercept is (0,4) which is where point B is located.\r
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\n" ); document.write( "\n" ); document.write( "We want to find the equation of the line through A(5,0) and B(0,4)
\n" ); document.write( "We need the slope
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\n" ); document.write( "\n" ); document.write( "\"m+=+%28y%5B2%5D+-+y%5B1%5D%29%2F%28x%5B2%5D+-+x%5B1%5D%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%284+-+0%29%2F%280+-+5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+%284%29%2F%28-5%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"m+=+-4%2F5\"
\n" ); document.write( "We know the y intercept since this line goes through B(0,4)
\n" ); document.write( "The y intercept always occurs when x = 0.\r
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\n" ); document.write( "\n" ); document.write( "We have m = -4/5 as our slope and b = 4 as the y intercept.\r
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\n" ); document.write( "\n" ); document.write( "Therefore, the slope-intercept equation \"y+=+mx%2Bb\" becomes \"y+=+-expr%284%2F5%29x%2B4\" which is the final answer.
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