document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198186>Question 1198186</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A billiard ball with a mass of 1.5 kg is moving at 25 m/s and strikes a second ball with a mass of 2.3 kg that is motionless. Find the velocity of the second ball if the first ball stops when it strikes the<BR>\n" );
document.write( "second ball. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #831737 by </B><A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><B>math_tutor2020(3817)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=math_tutor2020><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=831737\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font color=black size=3><BR>\n" );
document.write( "See this similar question<BR>\n" );
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document.write( "m1 = mass of the first ball<BR>\n" );
document.write( "vi1 = initial velocity of the first ball<BR>\n" );
document.write( "vf1 = final velocity of the first ball\r<BR>\n" );
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document.write( "m2 = mass of the second ball<BR>\n" );
document.write( "vi2 = initial velocity of the second ball<BR>\n" );
document.write( "vf2 = final velocity of the second ball\r<BR>\n" );
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document.write( "Due to the elastic collision, we can use this conservation of momentum formula<BR>\n" );
document.write( "m1*vi1 + m2*vi2 = m1*vf1 + m2*vf2\r<BR>\n" );
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document.write( "We have these values<BR>\n" );
document.write( "m1 = 1.5 kg<BR>\n" );
document.write( "m2 = 2.3 kg<BR>\n" );
document.write( "vi1 = 25 m/s<BR>\n" );
document.write( "vf1 = 0 m/s (since the 1st ball comes to a stop)<BR>\n" );
document.write( "vi2 = 0 m/s (the 2nd ball starts at rest)<BR>\n" );
document.write( "vf2 = x = unknown\r<BR>\n" );
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document.write( "Let's determine x<BR>\n" );
document.write( "m1*vi1 + m2*vi2 = m1*vf1 + m2*vf2<BR>\n" );
document.write( "1.5*25 + 2.3*0 = 1.5*0 + 2.3*x<BR>\n" );
document.write( "37.5 = 2.3x<BR>\n" );
document.write( "x = 37.5/2.3<BR>\n" );
document.write( "x = 16.304347826087<BR>\n" );
document.write( "x = 16\r<BR>\n" );
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document.write( "37.5 has 3 sig figs<BR>\n" );
document.write( "2.3 has 2 sig figs<BR>\n" );
document.write( "When dividing these items, we round to 2 sig figs since it's the smaller sig fig count.<BR>\n" );
document.write( "We go for the less accurate value.\r<BR>\n" );
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document.write( "Answer: 16 m/s<BR>\n" );
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