document.write( "Question 1198182: A cart weighing 40 lb is placed on a ramp inclined at 15° to the horizontal. The cart is held in place by a rope inclined at 60° to the horizontal, as shown in the figure. Find the force that the rope must exert on the cart to keep it from rolling down the ramp \n" ); document.write( "
Algebra.Com's Answer #831729 by ikleyn(52847)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A cart weighing 40 lb is placed on a ramp inclined at 15° to the horizontal. \n" ); document.write( "The cart is held in place by a rope inclined at 60° to the horizontal, \n" ); document.write( "as shown in the figure. Find the force that the rope must exert on the cart \n" ); document.write( "to keep it from rolling down the ramp \n" ); document.write( "~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " There is no any figure attached to the post.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "The force that the rope exerts on the cart is called \"rope tension\", or simply \"tension\".\r\n" ); document.write( "\r\n" ); document.write( "Let F be the tension.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Then it takes off F*sin(60°) from the weight W of the cart, leaving only W-F*sin(60°) as \r\n" ); document.write( "the net vertical force acting on the cart.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "This vertical force W-F*sin(60°) can be decomposed by the usual way into the sum \r\n" ); document.write( "of two vectors/(components), one parallel to the incline and the other normal to it.\r\n" ); document.write( " \r\n" ); document.write( "\r\n" ); document.write( "The component directed along the incline is (W-F*sin(60°))*sin(15°).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "This force/(component) is balanced by the component F*cos(60°- 15°) = F*cos(45°) directed along \r\n" ); document.write( "the incline in the opposite direction.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Thus the equilibrium equation is\r\n" ); document.write( "\r\n" ); document.write( " (W-F*sin(60°) )*sin(15°) = F*cos(45°).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "which gives\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " F =\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |