document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198181>Question 1198181</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Instruction: Solve and show your solution.<BR>\n" );
document.write( "Problem:<BR>\n" );
document.write( "     Find the resultant of A=30lbs upward and B=40lbs to the left. </SPAN>\n" );
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document.write( "Draw a right triangle with vertical leg 30 and horizontal leg 40.\r<BR>\n" );
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document.write( "We'll use a = 30 and b = 40 to find the following<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2%2Bb%5E2+=+c%5E2 ALIGN=MIDDLE  ALT=\"a%5E2%2Bb%5E2+=+c%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" > Pythagorean theorem\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c+=+sqrt%28a%5E2%2Bb%5E2%29 ALIGN=MIDDLE  ALT=\"c+=+sqrt%28a%5E2%2Bb%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c+=+sqrt%2830%5E2%2B40%5E2%29 ALIGN=MIDDLE  ALT=\"c+=+sqrt%2830%5E2%2B40%5E2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c+=+sqrt%28900%2B1600%29 ALIGN=MIDDLE  ALT=\"c+=+sqrt%28900%2B1600%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c+=+sqrt%282500%29 ALIGN=MIDDLE  ALT=\"c+=+sqrt%282500%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=c+=+50 ALIGN=MIDDLE  ALT=\"c+=+50\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "The hypotenuse is 50 units long.\r<BR>\n" );
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document.write( "This is a 30-40-50 right triangle based on the 3-4-5 right triangle (scale each side by a factor of 10).\r<BR>\n" );
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document.write( "The result vector is therefore 50 pounds upward and to the left.<BR>\n" );
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document.write( " </SPAN>\n" );
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