document.write( "Question 1198138: Between 6 p.m. and 7 p.m. the hands of a clock make a ninety-degree angle on two occasions. If Jenny always leaves home to walk her dog when the first ninety-degree angle is formed, and arrives home when the second is formed, how much time, in hours, does Jenny spend walking her dog every week? \n" ); document.write( "
Algebra.Com's Answer #831669 by ikleyn(52787)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "Between 6 p.m. and 7 p.m. the hands of a clock make a ninety-degree angle on two occasions. \n" ); document.write( "If Jenny always leaves home to walk her dog when the first ninety-degree angle is formed, \n" ); document.write( "and arrives home when the second is formed, how much time, in hours, \n" ); document.write( "does Jenny spend walking her dog every week? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "We will measure angles starting from the position of the hour and the minute hands vertically up, at 12:00 (midday, the noon).\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The minute hand makes one full rotation in one hour, so its angular velocity is 360 degrees per hour, or \r\n" ); document.write( "\r\n" ); document.write( " 360/60 = 6 degrees per minute.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The hour hand makes one full rotation in 12 hours, so its angular velocity is 360 degrees per 12 hours, or\r\n" ); document.write( "\r\n" ); document.write( " 360/12 = 30 degrees per hour = 30/60 = 0.5 degrees per minute.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "At 6:00 pm, the hour hand is in position 6*30 = 180 degrees from vertical position clockwise.\r\n" ); document.write( "\r\n" ); document.write( " The minute hand is in vertical position (= 0 degrees) at that time.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\"t\" minutes after 6:00 pm, the hour hand is in position 180 + 0.5t degrees from vertical up;\r\n" ); document.write( "\r\n" ); document.write( " the minute hand is in position 6t degrees.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "After 6:00 pm, the hour hand and the minute hand make the right angle for the first time, when 180 + 0.5t = 6t + 90 degrees.\r\n" ); document.write( "\r\n" ); document.write( "From this equation, we find \r\n" ); document.write( "\r\n" ); document.write( " 180 - 90 = 6t - 0.5t, or 5.5t = 90, t =\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "On clock problems, see my lessons\r \n" ); document.write( "\n" ); document.write( " - Clock problems \r \n" ); document.write( "\n" ); document.write( " - Advanced clock problems\r \n" ); document.write( "\n" ); document.write( "in this site.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |