document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198125>Question 1198125</A>: <I><SPAN STYLE=\"word-break: break-all;\">  A car drives 500 ft on a road that is inclined 12° to the horizontal. The car weighs 2500 lb. Thus gravity acts straight down on the car with a constant force F = -2500j. Find the work done by<BR>\n" );
document.write( "the car in overcoming gravity. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #831653 by </B><A HREF=/tutors/aboutme.mpl?userid=ikleyn><B>ikleyn(52786)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ikleyn><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ikleyn><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=831653\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .\r<BR>\n" );
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document.write( "Due to the &nbsp;Conservation &nbsp;Law of mechanical energy, &nbsp;the work done by the car engine<BR>\n" );
document.write( "is equal to the change of the potential energy of the car.\r<BR>\n" );
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document.write( "The change of the potential energy of the car is\r<BR>\n" );
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document.write( "    &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;2500*500*sin(12°) = 2500*500*0.2079 = 259875 lb*ft,  approximately.    &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;<U>ANSWER</U><BR>\n" );
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document.write( "Solved, answered and explained.\r<BR>\n" );
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