document.write( "Question 114249: Rewrite the middle term as the sum of two terms and then factor completely.\r
\n" ); document.write( "\n" ); document.write( "12w squared + 19w + 4
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Algebra.Com's Answer #83165 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"12w%5E2+%2B+19w+%2B+4=%28aw%2Bb%29%28cw%2Bd%29\"
\n" ); document.write( "Find a,b,c,d using the FOIL method (First, Outer, Inner, Last) and equating to the coefficients of your equation.\r
\n" ); document.write( "\n" ); document.write( "Now to expand the equation you use the FOIL method (First, Outer, Inner, Last)
\n" ); document.write( "\"%28aw%2Bb%29%28cw%2Bd%29\"
\n" ); document.write( "First : \"%28highlight%28aw%29%2Bb%29%28highlight%28cw%29%2B%28d%29%29=%28aw%29%28cw%29=acw%5E2\"
\n" ); document.write( "Outer : \"%28highlight%28aw%29%2Bb%29%28cw%2Bhighlight%28d%29%29=%28aw%29%28d%29=adw\"
\n" ); document.write( "Inner : \"%28aw%2Bhighlight%28b%29%29%28highlight%28cw%29%2B%28d%29%29=%28b%29%28cw%29=bcw\"
\n" ); document.write( "Last : \"%28aw%2Bhighlight%28b%29%29%28cw%2Bhighlight%28d%29%29=%28b%29%28d%29=bd\"
\n" ); document.write( "\"%28aw%2Bb%29%28cw%2Bd%29=%28ac%29%2Aw%5E2%2B%28ad%29%2Aw%2B%28bc%29w%2Bbd\"
\n" ); document.write( "\"%28aw%2Bb%29%28cw%2Bd%29=%28ac%29%2Aw%5E2%2B%28ad%2Bbc%29%2Aw%2Bbd\"
\n" ); document.write( "Comparing to your equation
\n" ); document.write( "\"12w%5E2+%2B+19w+%2B+4=%28ac%29%2Aw%5E2%2B%28ad%2Bbc%29%2Aw%2Bbd\"
\n" ); document.write( "1.\"ac=12\"
\n" ); document.write( "2.\"ad%2Bbc=19\"
\n" ); document.write( "3.\"bd=4\"
\n" ); document.write( "From 1, since ac=12, you can choose 12 and 1, 6 and 2, 4 and 3, and also 3 and 4, 2 and 6, and 1 and 12 for possible a-c combinations.
\n" ); document.write( "From 3, since bd=4, you can choose 4 and 1, 2 and 2, and 1 and 4 for possible b-d combinations.
\n" ); document.write( "Let's start with a=6 and c=2
\n" ); document.write( "From 2,
\n" ); document.write( "\"6d%2B2b=19\"
\n" ); document.write( "Notice the coefficients of b and d.
\n" ); document.write( "This solution set cannot be a solution because 2 even numbers will never sum to an odd number.
\n" ); document.write( "So 6 and 2 and 2 and 6 are out as possible a-c combinations.
\n" ); document.write( "Start again,
\n" ); document.write( "Let's choose a=12 and c=1,
\n" ); document.write( "From 2,
\n" ); document.write( "\"12%2Ad%2Bb=19\"
\n" ); document.write( "Now substitute possible b,d values.
\n" ); document.write( "\"12%2A1%2B4=16\" for b=4, d=1.
\n" ); document.write( "\"12%2A2%2B2=26\" for b=2, d=2.
\n" ); document.write( "\"12%2A4%2B1=49\" for b=1, d=4.
\n" ); document.write( "No solutions for a=12 and c=1.
\n" ); document.write( "Our last chance is 4 and 3.
\n" ); document.write( "Let's start with a=4 and c=3.
\n" ); document.write( "From 2,
\n" ); document.write( "\"4%2Ad%2B3%2Ab=19\"
\n" ); document.write( "Again, substitute possible b,d values.
\n" ); document.write( "\"4%2A1%2B3%2A4=16\" for b=4, d=1
\n" ); document.write( "\"4%2A2%2B3%2A2=14\" for b=2, d=2
\n" ); document.write( "\"4%2A4%2B3%2A1=19\" for b=1, d=4
\n" ); document.write( "Looks like a winner.
\n" ); document.write( "a=4,c=3,b=1,d=4
\n" ); document.write( "\"12w%5E2+%2B+19w+%2B+4=%284w%2B1%29%283w%2B4%29\"
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