document.write( "Question 1197909: An airline claims that the no-show rate for passengers booked on its flights is less than 6%. of 380 randomly selected reservations, 18 were no-shows. assuming that this data is used to test the airline's claim, find the p-value for the test. \n" ); document.write( "
Algebra.Com's Answer #831564 by Theo(13342)![]() ![]() You can put this solution on YOUR website! test mean is assumed to be .06. \n" ); document.write( "that's the value of p. \n" ); document.write( "the value of q is 1 - p = .94 \n" ); document.write( "sample size is 380. \n" ); document.write( "no shows are 18 from thqt sample. \n" ); document.write( "sample p = 18 / 380 = .047368411 = .047368 rounded to 6 decimal digits. \n" ); document.write( "standard error for the test = sqrt(p * q / n) \n" ); document.write( "p is the population proportion. \n" ); document.write( "q is equal to 1 minus the population proportion. \n" ); document.write( "n is equal to the sample size. \n" ); document.write( "standard error is therefore equal to sqrt(.06 * .94 / 380) = .01218 rounded to 5 decimal digits. \n" ); document.write( "z = (x-m)/s = (.047368 - .06) / .01218 = -1.037 rounded to 3 decimal digits. \n" ); document.write( "z is the z-score \n" ); document.write( "x is the sample proportion. \n" ); document.write( "m is the assumed population proportion. \n" ); document.write( "s is the standard error \n" ); document.write( "probability of z smaller than -1.037 = .1499 rounded to 4 decimal digits. \n" ); document.write( "that's the p-value for the test. \n" ); document.write( " \n" ); document.write( " |