document.write( "Question 1198048: One 1700-pound load of feed mixture contains 25% corn, 40% bran, and roughage. How many pounds of corn should be added to a load of feed mixture to make the feed 40% corn? \n" ); document.write( "

Algebra.Com's Answer #831561 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( "The original mixture is 1700 pounds, of which 25%, or 425 pounds, is corn.

\n" ); document.write( "Add x pounds of corn to the mixture; there are now 425+x pounds of corn, with a total of 1700+x pounds of mixture.

\n" ); document.write( "When that has been done, the corn is 40% (=2/5) of the mixture:

\n" ); document.write( " $\"%28425%2Bx%29%2F%281700%2Bx%29=2%2F5\"$
\n" ); document.write( " $\"5%28425%2Bx%29=2%281700%2Bx%29\"$
\n" ); document.write( " $\"2125%2B5x=3400%2B2x\"$
\n" ); document.write( " $\"3x=1275\"$
\n" ); document.write( " $\"x=425\"$

\n" ); document.write( "ANSWER: 425 pounds

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