document.write( "Question 1198036: he heights of adult men in America are normally distributed, with a mean of 69.2 inches and a standard deviation of 2.65 inches. The heights of adult women in America are also normally -distributed, but with a mean of 64.3 inches and a standard deviation of 2.59 inches.\r
\n" ); document.write( "\n" ); document.write( "a) If a man is 6 feet 3 inches tall, what is his z-score (to two decimal places)?\r
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\n" ); document.write( "\n" ); document.write( "b) If a woman is 5 feet 11 inches tall, what is her z-score (to two decimal places)?\r
\n" ); document.write( "\n" ); document.write( "z = \r
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\n" ); document.write( "\n" ); document.write( "c) Who is relatively taller?\r
\n" ); document.write( "\n" ); document.write( "-The 6 foot 3 inch American man
\n" ); document.write( "-The 5 foot 11 inch American woman
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Algebra.Com's Answer #831534 by ewatrrr(24785)\"\" \"About 
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Note: standard Normal Curve: µ = 0 and σ =1
\n" ); document.write( "for ex: to the right of center, z-score becomes larger as distance, in terms of σ from the mean, increases.
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\n" ); document.write( "Men Normal Distribution: µ = 69.2 and σ = 2.65
\n" ); document.write( "Women Normal Distribution: µ = 64.3 and σ = 2.59
\n" ); document.write( "z(man 75\") = ( 75 - 69.2)/2.65 = 2.1887
\n" ); document.write( "z(woman 71\") = (71 - 64.3)/2.59 = 2.5869****Represents More standard deviations from mean
\n" ); document.write( "c) Who is 'relatively taller?
\n" ); document.write( "-The 5 foot 11 inch American woman
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