document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1198027>Question 1198027</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If Joe can paint a house in 6 hours and Sam can paint<BR>\n" );
document.write( "the same house in 8 hours how long does it take <BR>\n" );
document.write( "them to do in working together  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #831530 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=831530\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is an alternative to the standard algebraic solution shown by one of the other tutors, and without using the shortcut shown by the other tutor.<br><BR>\n" );
document.write( "Consider the least common multiple of the two given times, which is 24 hours.<br><BR>\n" );
document.write( "In 24 hours, Joe could paint 24/6 = 4 of these houses; in 24 hours Sam could paint 24/8 = 3 of them.  So in 24 hours the two together could paint 4+3 = 7 houses.<br><BR>\n" );
document.write( "That means the number of hours it would take the two of them to paint the one house is 24/7.<br><BR>\n" );
document.write( "ANSWER: 24/7 hours<br><BR>\n" );
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