document.write( "Question 114255: If the sides of a square are decreased by 2 cm, the area is decreased by 36 cm squared. What were the dimensions of the original square? \n" ); document.write( "
Algebra.Com's Answer #83149 by Earlsdon(6294)\"\" \"About 
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Let x = the original length of each side of the square.
\n" ); document.write( "The original area is then:
\n" ); document.write( "\"A+=+x%5E2\"
\n" ); document.write( "Decreasing the sides by 2 cm. (x-2) results in the area being decreased by 36 sq. cm. (A - 36), so you can write:
\n" ); document.write( "\"%28x-2%29%5E2+=+%28A-36%29\" for the new area. Substitute \"A+=+x%5E2\" and solve for x.
\n" ); document.write( "\"%28x-2%29%5E2+=+x%5E2-36\" Simplify.
\n" ); document.write( "\"x%5E2-4x%2B4+=+x%5E2-36\" Subtract \"x%5E2\" from both sides.
\n" ); document.write( "\"-4x%2B4+=+-36\" Subtract 4 from both sides.
\n" ); document.write( "\"-4x+=+-40\" Divide both sides by -4.
\n" ); document.write( "\"x+=+10\"cm.
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