document.write( "Question 1197998: 8. If y varies inversely as x. If y = 15 when x = 3, find y when x = 1.\r
\n" ); document.write( "\n" ); document.write( "A. 45
\n" ); document.write( "B. 4.5
\n" ); document.write( "C. 18
\n" ); document.write( "D. 5
\n" ); document.write( "E. 1/5
\n" ); document.write( "F. 0.45\r
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\n" ); document.write( "\n" ); document.write( "9. If p varies inversely proportional to q. If q = 6 when p = 18, find q when p = 10.\r
\n" ); document.write( "\n" ); document.write( "A. 1/3
\n" ); document.write( "B. 3
\n" ); document.write( "C. 60
\n" ); document.write( "D. 10.8
\n" ); document.write( "E. 28
\n" ); document.write( "F. 180\r
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\n" ); document.write( "\n" ); document.write( "10. If r varies inversely with w - 1. If r = 3/50 when w = 3, find r when w is 10.\r
\n" ); document.write( "\n" ); document.write( "A. 75
\n" ); document.write( "B. 10
\n" ); document.write( "C. 175
\n" ); document.write( "D. 1/75
\n" ); document.write( "E. 1/750
\n" ); document.write( "F. 1/175
\n" ); document.write( "

Algebra.Com's Answer #831486 by josgarithmetic(39621)\"\" \"About 
You can put this solution on YOUR website!
The language for these works in a very consistent way.\r
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\n" ); document.write( "\n" ); document.write( "8:
\n" ); document.write( "\"y=k%2Fx\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "9:
\n" ); document.write( "\"p=k%2Fq\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "10:
\n" ); document.write( "Seems to be saying, \"r=k%2F%28w-1%29\".
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