document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1197978>Question 1197978</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A passenger train leaves a train station on schedule. A freight train had departed from the same station 2hours before the passenger taron. The passenger train is headed in the same direction as the freight train at an average speed of 16km/hr. The passenger train catches up with the freight train in 4hours and overtakes it. Calculate speed of the freight train </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #831473 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=831473\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "At the time when the passenger train has caught up with the freight train, the distances the two trains have traveled are the same.<br><BR>\n" );
document.write( "At that time, the passenger train has been traveling for 4 hours and the freight train has been traveling for 6 hours.<br><BR>\n" );
document.write( "The distances are the same, and the ratio of times is 6:4 = 3:2; that means the ratio of speeds is 2:3.  So the speed of the freight train is 2/3 the speed of the passenger train.<br><BR>\n" );
document.write( "ANSWER: 16*(2/3) = 32/3 km/hr<br><BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );